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Two natural numbers differ by 4 and the sum of their squares is 58 . Find the numbers
October 24, 2015 at 2:28pm
let number 1 be x and number 2 be (x + 4). [ieqn]x^2+(x+4)^2=58[/ieqn] [ieqn]x^2+x^2+8x+16=58[/ieqn] [ieqn]2x^2+8x-42=0[/ieqn] [ieqn]x^2+4x-21=0[/ieqn] [ieqn](x+7)(x-3)=0[/ieqn] x = -7(N.A), 3 Number 1 = 3 Number 2 = 3 + 4 = 7
October 25, 2015 at 9:15am
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