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hamidali
:
Z=( 1,2 ) then find out what is the value of z ^-1
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December 6, 2015 at 3:32pm
Shu Yun
:
z = 1 +2i = [ieqn]z=\sqrt{5}e^{i\tan^{-1}2}[/ieqn] [ieqn]z^{-1}=\frac{1}{\sqrt{5}}e^{-i\tan^{-1}2}\\ z^{-1}=\frac{1}{\sqrt{5}}[cos(\tan^{-1}2)-isin(\tan^{-1}2)][/ieqn]
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December 7, 2015 at 3:54am
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