Sin(X+45) =0.5 .. Range is 0<X<360 how to solve!!

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Mercedes: Sin(X+45) =0.5 .. Range is 0<X<360 how to solve!!

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February 12, 2017 at 9:51am

Little Sky:let [ieqn]\alpha[/ieqn] be the basic angle (x + 45). [deqn]\sin\alpha=0.5[/deqn][deqn]\alpha=30^\circ[/deqn]Because the basic angle is positive, it lies in 1st and 2nd quadrant. So,[deqn]x+45^\circ=30^\circ,180^\circ-30^\circ=150^\circ,360^\circ+30^\circ=390^\circ\\x=-15^\circ(Not Applicable),105^\circ, 345^\circ[/deqn]
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- February 12, 2017 at 3:27pm

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