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amia
:
find lim (sinx)/(x - 3pi) as x goes to 3pi
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January 10, 2018 at 3:34pm
Kho Yen Hong
:
Lets see....[deqn]\sin x = (\cos x \sin 3\pi - \sin x \cos3\pi) = \sin(3\pi-x) = - \sin(x-3\pi)[/deqn]So your whole limit can be rewrite as:[deqn]\lim_{x \rightarrow 3\pi} -\frac{\sin(x-3\pi)}{x-3\pi}= -1[/deqn]since[deqn]\lim_{\theta \rightarrow 0} \frac{\sin\theta}{\theta} =1[/deqn]
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November 25, 2018 at 11:19am
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